path 'g' in 'http:g' becomes '/g'.

    >>> urlsplit('http:g')
    SplitResult(scheme='http', netloc='', path='g', query='', fragment='')
    >>> urlunsplit(urlsplit('http:g'))
    'http:///g'
    >>> urlsplit('http:///g')
    SplitResult(scheme='http', netloc='', path='/g', query='', fragment='')

    >>> urljoin('http://a/b/c/d', 'http:g')
    'http://a/b/c/g'
    >>> urljoin('http://a/b/c/d', 'http:///g')
    'http://a/g'

The problematic part of the code is:

    def urlunsplit(components):
        [...]
        if netloc or (scheme and scheme in uses_netloc and url[:2] != '//'):
--->        if url and url[:1] != '/': url = '/' + url
            url = '//' + (netloc or '') + url

Note also that urllib has decided on the interpretation of 'http:g' (in test).

    def test_RFC3986(self):
        [...]
        #self.checkJoin(RFC3986_BASE, 'http:g','http:g') # strict parser
        self.checkJoin(RFC3986_BASE, 'http:g','http://a/b/c/g') #relaxed parser

@op368 I don't think that this is a bug, [1] literally uses this exact example and shows the expected behaviour. 


[1] https://datatracker.ietf.org/doc/html/rfc3986#section-5.4.2

hello, @jaswdr, but I can't understand what's wrong with my point.
What is 'the expected behaviour'?

@op368 as far as I can see, regarding of any miss interpretation, yes, the RFC has this section:

      "http:g"        =  "http:g"         ; for strict parsers
                      /  "http://a/b/c/g" ; for backward compatibility

What I can understand is that for "http:g" it will be translated to "http:///g" because of backward compatibility, this seems to be an edge case for the parser, since the RFC text also mention that this should be avoided.

'http:///g' has absolute path '/g',
and as urljoin shows:

    >>> urljoin('http://a/b/c/d', 'http:///g')
    'http://a/g'  # 'a' is netloc

So you are proposing third interpretation.

      "http:g"        =  "http:g"         ; for strict parsers
                      /  "http://a/b/c/g" ; for backward compatibility
                      /  "http://a/g"     ; (yours)

Not exactly, in the RFC example they use a/b/c for the path, but when using http:g there is no nested path, so it should be http:///g, no?

I tried hard (even read RFC1630),
but I think no.